4(x^2+4x+2x+8)=12x

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Solution for 4(x^2+4x+2x+8)=12x equation: 



4(x^2+4x+2x+8)=12x

We move all terms to the left:

4(x^2+4x+2x+8)-(12x)=0

We add all the numbers together, and all the variables

-12x+4(x^2+4x+2x+8)=0

We multiply parentheses

4x^2-12x+16x+8x+32=0

We add all the numbers together, and all the variables

4x^2+12x+32=0

a = 4; b = 12; c = +32;
Δ = b2-4ac
Δ = 122-4·4·32
Δ = -368
Delta is less than zero, so there is no solution for the equation

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